f(x)=asin(x)+bx3 <<<< is it x2 or x3
f'(x)=acos(x)+3bx2
f''(x)=-asin(x)+6bx
f'''(x)=-acos(x)+6b
f(iv)(x)=asin(x)+6b >>>>> that 6b should not be there
Are these correct? What do we do next?
Ohhh and....
It's f(x)=asin(x)+bx^2 ...sorry about that
Which means all the derivatives change a little bit from what I had before.
f(x)=asin(x)+bx2
f'(x)=acos(x)+2bx
f''(x)=-asin(x)+2b
f'''(x)=-acos(x)
f(iv)(x)=asin(x)
Are these correct now? .....................Yes