Derivative

[Guest]

y=e^xlnx,x>0

I got e^x(lnx+x)/x is this right.

 

[tkhunny]

Nope. Something went haywire. Show your steps and let's see if we can track it down.

 

[Guest]

(e^x)(1/x)+lnx (e^x)

 

[Unco]

Correct, well done!

 

[Guest]

that is what I got but that is not one of the choices

1. e^x/x

2.e^x lnx

3. e^x (x ln x +1)/x

 

[Unco]

(e^x)(1/x)+lnx(e^x)

There is a common factor of e^x:

e^x [ (1/x) + lnx ]

So your answer is equivalent to the third option.

 

[Guest]

ha thank you