y=(3x^2+5x+1)^3/2 I am not sure how to set this up
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Oct 19, 2005 #2 That is a lovely equation. What is the problem statement. Note: Look up "chain rule"
G Guest Guest Oct 19, 2005 #3 Find the derivative Sorry I am new to this. I will get better thanks for you help!!!
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Oct 19, 2005 #4 amy2310 said: y=(3x^2+5x+1)^3/2 I am not sure how to set this up Click to expand... Notice the nested structure: f(x) = x^(3/2) g(x) = 3x^2 + 5x + 1 f'(x) = (3/2)*x^(1/2) g'(x) = 6*x + 5 If you can do those, you can do the problem as stated, using the Chain Rule. y' = [(3/2)*(3x^2+5x+1)^(1/2)]*(6*x + 5)
amy2310 said: y=(3x^2+5x+1)^3/2 I am not sure how to set this up Click to expand... Notice the nested structure: f(x) = x^(3/2) g(x) = 3x^2 + 5x + 1 f'(x) = (3/2)*x^(1/2) g'(x) = 6*x + 5 If you can do those, you can do the problem as stated, using the Chain Rule. y' = [(3/2)*(3x^2+5x+1)^(1/2)]*(6*x + 5)