Derivative

[calculus1]

If t(x) = x^3 −5x and y(x) = x^2 −4x^3, find the value
of d^2y/dt^2 at t = −2.

can you help with this question? I could find its value at x =-2 but I couldn't figure out how to use t= -2.

 

[Deleted member 4993]

If t(x) = x^3 −5x and y(x) = x^2 −4x^3, find the value
of d^2y/dt^2 at t = −2.

can you help with this question? I could find its value at x =-2 but I couldn't figure out how to use t= -2.

Please share your work - from the beginning and in detail.

 

[Dr.Peterson]

If t(x) = x^3 −5x and y(x) = x^2 −4x^3, find the value
of d^2y/dt^2 at t = −2.

can you help with this question? I could find its value at x =-2 but I couldn't figure out how to use t= -2.

We do need to see your work in order to know what you are missing; but one thing that will help is to look at t = x^3 −5x and try to determine what x is when t = -2.

 

[Deleted member 4993]

If t(x) = x^3 −5x and y(x) = x^2 −4x^3, find the value
of d^2y/dt^2 at t = −2.

can you help with this question? I could find its value at x =-2 but I couldn't figure out how to use t= -2.

Did you use:
dy/dt = dy/dx * dx/dt .......................→ dy/dt = (dy/dx) / (dt/dx) ............ (added later)