Derivative x^2*e^(2-x) at (2,4)

[rj686]

I just took a test and i think i screwed up

I got the derivative at x=2 to be 0.....

F'(x)= 2x*e(2-x)-x^2*e^(2-x)

that's what i got for the derivative but i dont think its correct

 

[soroban]

Hello, rj686!

\(\displaystyle \L F(x)\:=\:x^2\cdot e^{2-x}\) at $\displaystyle (2,4)$

I got the derivative at $\displaystyle x = 2$ to be $\displaystyle 0.$ . . . so did I!

\(\displaystyle \L F'(x) \:= \:2x\cdot e^{^{2-x}}\,-\,x^2\cdot e^{^{2-x}}\)

Looks good to me!