Derivative x^2*e^(2-x) at (2,4)

rj686

New member
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Mar 28, 2006
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I just took a test and i think i screwed up

I got the derivative at x=2 to be 0.....

F'(x)= 2x*e(2-x)-x^2*e^(2-x)

that's what i got for the derivative but i dont think its correct :(
 
Hello, rj686!

\(\displaystyle \L F(x)\:=\:x^2\cdot e^{2-x}\) at \(\displaystyle (2,4)\)

I got the derivative at \(\displaystyle x = 2\) to be \(\displaystyle 0.\) . . . so did I!

\(\displaystyle \L F'(x) \:= \:2x\cdot e^{^{2-x}}\,-\,x^2\cdot e^{^{2-x}}\)

Looks good to me!

 
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