What is the derivative of (e^e^X)?
U Unco Senior Member Joined Jul 21, 2005 Messages 1,134 Jan 28, 2006 #2 It's no scarier than what you're used to with \(\displaystyle \mbox{e^{ax}}\). \(\displaystyle \L \mbox{ \frac{d}{dx} e^{(e^x)} = e^x\cdot e^{(e^x)}}\)
It's no scarier than what you're used to with \(\displaystyle \mbox{e^{ax}}\). \(\displaystyle \L \mbox{ \frac{d}{dx} e^{(e^x)} = e^x\cdot e^{(e^x)}}\)
M mathstresser Junior Member Joined Jan 28, 2006 Messages 134 Jan 28, 2006 #3 Use u-substitution. u=e^x du=e^x the derivative of e^u is e^u(du) then you have (e^x)(e^(e^x))
