derivative of y = x^2 e^-2x

[math1325]

Find derivative of y=x^2e^-2x.

this is what i did so far

f(x)=u(X)*v(X)+V(x)*u(x)
=(x^2)*(e^-2x)+(2x)(-2xe^-3x)
=x^2e^-2X+-4x^2e^-3x

 

[skeeter]

no ...

y = x²e^-2x

dy/dx = x²(-2e^-2x) + e^-2x(2x)

dy/dx = 2xe^-2x(-x + 1) = 2xe^-2x(1 - x)

 

[math1325]

can you please post that in the right format bcz I am not able to understand the "sup"...what is that.

 

[pka]

\(\displaystyle \L
\begin{array}{l}
y = x^2 e^{ - 2x} \\
y' = \left( {2x} \right)\left[ {e^{ - 2x} } \right] + \left[ {x^2 } \right]\left( { - 2e^{ - 2x} } \right) \\
\end{array}\)

math1325
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