Derivative of y= ln(x^2e^(3x))

[vashi123]

Find y' of y = ln(x^2e^(3x))

I really don't know where to start with this one. I know the chain rule must be applied but I can't remember how to do it! Could anyone help me out please? Thanks

 

[pka]

\(\displaystyle \ln \left( {x^2 e^{3x} } \right) = \ln \left( {x^2 } \right) + \ln \left( {e^{3x} } \right) = 2\ln (x) + 3x\)

 

[vashi123]

im so dumb lol i totally forgot about adding them. thanks alot.