Can someone show me how to take the derivative of the cosine law: cos(C)=((a^2)+(b^2)+(c^2))/(2ab)
S sameg New member Joined Mar 15, 2006 Messages 1 Mar 15, 2006 #1 Can someone show me how to take the derivative of the cosine law: cos(C)=((a^2)+(b^2)+(c^2))/(2ab)
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Mar 15, 2006 #2 With respect to which variable are you taking the derivative? How far have you gotten? Thank you. Eliz.
With respect to which variable are you taking the derivative? How far have you gotten? Thank you. Eliz.
