is the derivative of THIS integral the upper boundary of the function (as it should be?)?
d/dt (Int_{0,t}dt' sin(w(t-t')) V'(Q(t'))) =? sin(wt) V'(Q(t))
derived in the same way as it works for just 1 function d/dx Int_{0,x} dx' f(x') = f(x) ???
d/dt (Int_{0,t}dt' sin(w(t-t')) V'(Q(t'))) =? sin(wt) V'(Q(t))
derived in the same way as it works for just 1 function d/dx Int_{0,x} dx' f(x') = f(x) ???