derivative of an ecponent

[reaper_pball69]

can some tell me how to get the derivative of
y= sqrt(x^3+e^-x+5)

I need to know how to get it to. Thank you for your help

 

[stapel]

It might help to rewrite this in exponential form:

. . . . .y = [x³ + e^-x + 5]^(1/2)

Then apply the Chain Rule by first differentiating the 1/2 power, and then multiplying by the derivative of x³ + e^-x + 5.

Eliz.

 

[Guest]

y = [x^3 + e^-x + 5]^(1/2)

y= u ^(1/2) where u = x^3 +e^(-x) + 5

dy/du = 1/2 u (-1/2) du/dx = 3 x^2 - e(-x)

dy/dx = dy/du x du/dx

= (1/2 (x^3 +e^(-x) + 5))^ (-1/2) (3 x^2 - e(-x) )

:shock:

 

[tkhunny]

...except for the missing exponent.

e^(-x), not e(-x).

Maybe it ws just a typo.