derivative of a negative exponential function

Mickey

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May 7, 2009
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The re-growth of a population of rabbits in an area is given by the function
P(t) = 500 divided by 1 + e^-t where t is the time in years. how can I determine the rate of growth in the population after 3 years. I know it is necessary to get the derivative of P(t) but and substitute in t =3 but I don't know how to get derivative of (1 + e^-t)^-1
Please help me.
 
\(\displaystyle \frac{d}{dt}\left[\frac{1}{1+e^{-t}}\right]\)

Quotient rule:

\(\displaystyle \frac{(1+e^{-t})(0)-(1)(-e^{-t})}{(1+e^{-t})^{2}}=\frac{e^{-t}}{(1+e^{-t})^{2}}\)

This seems like deja vu all over again. viewtopic.php?f=3&t=34161
 
galactus said:
This seems like deja vu all over again. ...

Yep ... if you just observe - you can see lot of things.....
 
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