Derivative hlep

palangi

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Sep 19, 2010
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Can someone tell me if I did this problem correctly?

Find the derivative: y=2-3x/sqrt(4x+1)

y'=(0-3)(4x+1)^(1/2) - (2+3x)[1/2(4x+1)^-1/2](4)

y'= -3sqrt(4x+1) + 12x-8/2sqrt(4x+1)

Thank you
 
palangi said:
Find the derivative: y = 2 - 3x/sqrt(4x + 1)

Your typing means this:

\(\displaystyle y \;=\; 2 \;-\; \frac{3x}{\sqrt{4x + 1}}\)

Based on your work below, I think the given equation is this:

y = (2 - 3x)/sqrt(4x + 1)

In other words, the numerator is 2 - 3x, and we show that by typing grouping symbols around it.



y ' = (0 - 3)(4x + 1)^(1/2) - (2 + 3x)[1/2(4x + 1)^-1/2](4) This looks mostly correct.

The factor (2 + 3x) should be (2 - 3x).

The denominator is missing; I mean, the entire expression above should be over [sqrt(4x + 1)]^2

After correcting and simplifying, I get:

y` = -(6x + 7)/(4x + 1)^(3/2)

Cheers ~ Mark 8-)

 
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