killasnake
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I know how to take the Derivative for a much simpler question but I have no idea how to do it with this one. Do I get rid of the square root first or something? :?
Derivative help: f(x) = 6x^6 sqrt[x] + 2/(x^2 sqrt[x])
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I know how to take the Derivative for a much simpler question but I have no idea how to do it with this one. Do I get rid of the square root first or something? :?
Re: Derivative help
Hello, killasnake!
Have you never run into a square root before
Are you familiar with the Product Rule?
Actually, it's simpler than you think . . .
We have: \(\displaystyle \L\:f(x)\;=\;6x^5\sqrt{x}\,+\,\frac{2}{x^2\sqrt{x}} \;= \;6x^5x^{\frac{1}{2}}\,+\,\frac{2}{x^2x^{\frac{1}{2}}}\)
Hence: \(\displaystyle \L\:f(x) \;= \;6x^{\frac{11}{2}}\,+\,2x^{-\frac{5}{2}}\)
Can you finish it now?
Hello, killasnake!
Have you never run into a square root before
Are you familiar with the Product Rule?
Actually, it's simpler than you think . . .
We have: \(\displaystyle \L\:f(x)\;=\;6x^5\sqrt{x}\,+\,\frac{2}{x^2\sqrt{x}} \;= \;6x^5x^{\frac{1}{2}}\,+\,\frac{2}{x^2x^{\frac{1}{2}}}\)
Hence: \(\displaystyle \L\:f(x) \;= \;6x^{\frac{11}{2}}\,+\,2x^{-\frac{5}{2}}\)
Can you finish it now?
killasnake
Junior Member
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- Sep 11, 2005
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We acutally learned the Product Rule in the last 5 mins of class yesterday so we haven't gone in depth about it yet. I just wanted to try and get ahead in my homework.
Let me try to work it out and i'll get back to you.
Let me try to work it out and i'll get back to you.
killasnake
Junior Member
- Joined
- Sep 11, 2005
- Messages
- 55
Umm I can't seem to get the right answer, I took the derivative and I came up with 2 answers which or uncorrect:
