derivative: 2^(1-x) find f'(x)

Re: derivative

Use \(\displaystyle \frac{d}{dx}[b^{u}]=b^{u}ln(b)\cdot\frac{du}{dx}\)
 
ssabadnama3 said:
2^(1-x) find f'(x)

another way:

\(\displaystyle 2^{1-x} \, = \, \frac{2}{2^x}\)

Now you can use standard formulae.
 
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