if dy/dx = ((6x^2) + 4))/ y and y = 4 when x = 1, then when x = 0, y =?
G Guest Guest Dec 18, 2005 #1 if dy/dx = ((6x^2) + 4))/ y and y = 4 when x = 1, then when x = 0, y =?
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Dec 18, 2005 #2 dy/dx = ((6x^2) + 4))/ y y*dy = ((6x^2) + 4))*dx (1/2)y^2 = 2x^3+4x+C Plug in (1,4) and solve for C Plug in x=0 and solve that for y
dy/dx = ((6x^2) + 4))/ y y*dy = ((6x^2) + 4))*dx (1/2)y^2 = 2x^3+4x+C Plug in (1,4) and solve for C Plug in x=0 and solve that for y
