Definite Integral

abilitiesz

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Hello,

I need some help on my calculus homework. I've tried each problem roughly 10-20 times, but I keep getting the wrong answer. Any help is appreciated. Thank you.
 

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Are you actually sitting in the exam right now?

These are textbook examples of "Substitution".

Hints:
ddxln(x)=1x\displaystyle \frac{d}{dx} \ln(x) = \frac{1}{x}

ddxx5=5x4\displaystyle \frac{d}{dx} x^{5} = 5x^{4}

Now, go to! Harvest the field of integrals before it is past the time for reaping!!
 
Oh, no. I'm not sitting in an exam lol. I'm at home trying to do hw. I hate internet assignments. :? You have to enter it in perfectly otherwise the system wont see it as a correct answer. It's a pain. Thank you for the advice. I'll try it out now and see if I can get the results.
 
x4cos(x5)dx\displaystyle \int x^{4}cos(x^{5})dx

Let u=x5,   du=5x4dx\displaystyle u=x^{5}, \;\ du=5x^{4}dx

Now, see it?. The sub is rather easy and turns it into an easy integral.

1xln(x)dx\displaystyle \int\frac{1}{x\sqrt{ln(x)}}dx

Let u=ln(x),   du=1xdx\displaystyle u=ln(x), \;\ du=\frac{1}{x}dx
 
ee9dxxlnx Let u = lnx, then du = 1xdx\displaystyle \int_{e}^{e^9} \frac{dx}{x\sqrt ln|x|} \ Let \ u \ = \ ln|x|, \ then \ du \ = \ \frac{1}{x}dx

Ergo,we have 19duu1/2 = 2u1/2]19 = 4.\displaystyle Ergo, we \ have \ \int_{1}^{9} \frac{du}{u^{1/2}} \ = \ 2u^{1/2}\bigg]_{1}^{9} \ = \ 4.
 
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