Use a definite intergral with this cost per foot function, y=10(1.014)^x, to calcualte the total costs of a 200 foot well.
I'm a little confused... but here is what I did.
I integrated the function using: (a^x)/ lna
So I said [10(1.014^x) ]/ ln 1.014
Then I plugged in 200 for x and came up with 11600.
I'm not sure about this... any help you can offer is much appreciated!
I'm a little confused... but here is what I did.
I integrated the function using: (a^x)/ lna
So I said [10(1.014^x) ]/ ln 1.014
Then I plugged in 200 for x and came up with 11600.
I'm not sure about this... any help you can offer is much appreciated!