dealing with volume in a spherical balloon

kggirl

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Oct 5, 2005
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A spherical balloon is being inflated. The volume = 4/3pi r^3 When r = 10.0 cm, the radius is increasing at the rate of dr/dt = 1.00cm/s. How fast is the volumeincreasing at that time? (What is the dV/dt?)
 
V=4/3pi r<sup>3</sup>

You have to differentiate in respect to time (t)

dV/dt=4pi r<sup>2</sup> dr/dt

You know dr/dt. and you know r for that time
 
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