D > (131,700,000)/(10^{0.1400t}), D: time in days, t: degrees Celsius

[Kingsx]

Help me understand how to work this. Just need some help understanding how to properlly solve this on a calculator.

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\(\displaystyle D\, >\, \dfrac{131,700,000}{10^{0.1400\, t}}\)

\(\displaystyle D:\, \mbox{time in days}\)

\(\displaystyle t:\, \mbox{temperature in degrees Celsius}\)

---

the Celsius is 55

 

[stapel]

Help me understand how to work this

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\(\displaystyle D\, >\, \dfrac{131,700,000}{10^{0.1400\, t}}\)

\(\displaystyle D:\, \mbox{time in days}\)

\(\displaystyle t:\, \mbox{temperature in degrees Celsius}\)

---

the Celsius is 55

Lacking instructions, it is difficult to know what it is that need to be "worked". Are you maybe supposed to "evaluate" and give the "solution interval"?

When you reply, please provide a clear listing of your thoughts and efforts so far, along with a specification of where you're getting bogged down. Thank you!

 

[Kingsx]

I need to know what the time in minutes/days would be using this formula with the t being 55celsius

this is a pathogen reduction formula for composting biosolids once temperatures reach 55celsius. It is the formula used to determine time at 55 Celsius for pathogen reduction to be considered completed.
So far I get .1400x55=7.7
i assume you then take 10 to the 10th power but I'm not sure how to combine the 10 and the 7.7 correctly scientifically and so on to get your bottom number that needs to be divided into the top number of 131,700,000 to =days/minutes ?

 

[Kingsx]

I'm needing someone to show how they would work this formula.
The t=55
I'm not sure how to do the bottom part of this formula
i assume you take the .1400X55=7.7 for part of the bottom equation?
i keep getting 2.62 days for a answer and not sure that is right

 

[ksdhart2]

I'm needing someone to show how they would work this formula.
The t=55
I'm not sure how to do the bottom part of this formula
i assume you take the .1400X55=7.7 for part of the bottom equation?
i keep getting 2.62 days for a answer and not sure that is right

You haven't even told us what the problem is! If we don't know what you were tasked with doing, how can we possibly know if your answer is correct or not? If the task was to solve for the number of days, given a specific temperature, then your answer is correct. If the task were literally anything else, your answer may or may not be correct. I'll try asking again, in explicit could-not-in-any-way-be-misconstrued terms: Please post the full and exact problem text, quoting word-for-word exactly as it was presented to you from your textbook/handout.

 

[mmm4444bot]

i assume you take the .1400X55=7.7 for part of the bottom equation?

The "bottom" is not an equation; it's an expression. We call it the denominator.

And, what you're calling "part" also has a name. We call it the exponent.

If you're evaluating the right-hand side of the given inequality, when t=55, then your assumption is correct.

You substitute 55 for symbol t.

Order of Operations requires calculating the value of the exponent first, and 7.7 is correct.

i keep getting 2.62 days for a answer and not sure that is right

That's close, but it's not properly rounded.

Were you instructed to round to the nearest hundredth of a day?

If not, I would round to the nearest tenth of a day. :cool:

 

[Kingsx]

You haven't even told us what the problem is! If we don't know what you were tasked with doing, how can we possibly know if your answer is correct or not? If the task was to solve for the number of days, given a specific temperature, then your answer is correct. If the task were literally anything else, your answer may or may not be correct. I'll try asking again, in explicit could-not-in-any-way-be-misconstrued terms: Please post the full and exact problem text, quoting word-for-word exactly as it was presented to you from your textbook/handout.

Then my task is done and that's all I needed. Thank you and if I needed anything other than days in time with the given 55 Celsius I would've asked. Beat a Dead horse elsewhere,Mathelete Hero!
This is the equation used for composting rules per Texas environmental Quality permitted requirements.
Simple thing I think I was just needing to get clarification that I'm getting close to understanding it or close on my answer.