CYCLE-IN TRIANGLE

H

hope

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Joined
May 11, 2005
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12
HELLO!

PLEASE HELP ME ONCE AGAIN !!
MY NEW PROBLEM IS THIS:(PROMISE WON`T WRIGHT FOR SOME TIME)

WELL: If there is cycle inscribed in isosceles triangle and his center divides height in ratio(proportion) 12:5 , and side of triangle is 60 cm ,question is how long is the base of triangle(another side)??
Result is 50cm??How??
I`do not know how long is the height ,there is connection between ratio(12:5)and height and radius of cycle but...???
Please if you have patience ,show me step by step...
Thanks once more!!!
 
hope said:
HELLO!
PLEASE HELP ME ONCE AGAIN !!
MY NEW PROBLEM IS THIS:(PROMISE WON`T WRIGHT FOR SOME TIME)
WELL: If there is cycle inscribed in isosceles triangle and his center divides height in ratio(proportion) 12:5 , and side of triangle is 60 cm ,question is how long is the base of triangle(another side)??
Result is 50cm??How??
I`do not know how long is the height ,there is connection between ratio(12:5)and height and radius of cycle but...???
Please if you have patience ,show me step by step...
Thanks once more!!!
Click to expand...

C'mon hope...cycle? Is that a bicycle?
Do you mean CIRCLE?
Do you know what an isosceles triangle is?
Did you draw one, then put in a circle...just to see what it all looks like?
 
I`am so sorry for my bad english , yes I` did mean circle.

WORK DONE :

12:5=2/3h:1/3h
12=2/3h
v=18
5=1/3h
h=15
18+15=33(height)
a=sqrt(60^2-33^2)(a=side)

a=50,1098??? I` know that this is wrong way but I` do not know
different.

r=a*sqrt(3)/6?? I` do not know how to make a connection between this
and ratio 12:5.

So if you want to help me OK if not that is OK to. Thank you for your constructive criticism.

[/code]
 
Sorry...didn't realise you had English problems;
I see you saw the solution at another site; good.

By the way, English is easy to "get"; my mother tongue
is French, but now I find English easier than French;
same should happen to you...
 
This may help you if you get similar problems (isosceles triangles involved).

Remember that an isosceles triangle is 2 right triangles stuck together;
as example, you can take 2 right triangles with dimensions 36-48-60,
stick them together along the side=48, and you get isosceles triangle
size 60-60-72, with height 48.

The inscribed circle is easy to figure out; if you let the sides of the right
triangle = a,b,c (b = height, c = hypotenuse), then the radius of circle is simply:
ab / (a + c).
For the 36-48-60, or isosceles 60-60-72 case: 36*48 / (36 + 60) = 18.

Hope that helps.
 
WHAT?! The same question by Mathxyz? And on same day...

Hey hope, are you his girlfriend?
 
No,do not worry I`am not his girlfriend.

OK,I´think owe you an explanation.I`am working and do not have very much time to spend on computer.I´also trying to go back to school but have ˝SOME˝hole in math , and I` was looking for some help .Since I` already explain I` do not have all the time access to computer so I` just copy paste my Question and send it to all free math help forum because I` thought that not so many people would help.SO THANK YOU ALL ONCE AGAIN.
AND JUST ONE MORE THING (IT DOES NOT JUSTIFIED ME OR MY BAD ENGLISH)but since I` was in a hurry and had a quick look in dictionary overlook a right word for my question I` put cycle instead of circle.
And since I` caused such ˝commotion˝I´will not write for some time.
By..
 
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