cxd=0, Therefore, Vector c is a scalar multiple of vector d?

[shivers20]

cxd=0, Therefore, Vector c is a scalar multiple of vector d? Can someone explain this to me? How would I go about finding if this is true. Thanks

 

[arthur ohlsten]

CxD=0
lCl lDl sin @ =0

if C is not 0, and D is not 0, then @ must =0 degrees or 180 degrees.

Then C and D must be scaler multiples.

I hope thgis is acceptable to your instructor
Arthur