curve sketching

[Guest]

Sketch the graph of y=-5x^2+3x/2x^2-5

x-intercept(3/5,0)
y-intercept(0,0)
vertical asymptotex=-1.58,1.58
horizontal asymptote y=-5/2
y'=-6x^2+50x-15/(2x^2-5)^2
critical points y'=0 x=?
-6x^2+50x-15=0
y''=?
can you continue this quiestion?
please help me.

 

[stapel]

Sketch the graph of y=-5x^2+3x/2x^2-5

What you have posted (above) means the following:

. . . . .y = -5x² + (3x/2x²) - 5x

Did you omit some parentheses? Did you actually mean the following?

. . . . .y = (-5x² + 3x) / (2x² - 5x)

can you continue this quiestion?

The instructions (as posted, anyway) only say to "sketch". So pick some x-values, find the corresponding y-values, plot the points, and, once you've got enough dots, draw the line.

Or were there further instructions regarding the tasks you need to complete...?

Eliz.

 

[Guest]

Sketch the following functions, showing all work needed to sketch each curve.

y = (-5x^2 + 3x) / (2x^2-5)

 

[stapel]

Sketch the following functions, showing all work needed to sketch each curve.

y = (-5x^2 + 3x) / (2x^2-5)

So would that mean that, yes, I'd guessed your meaning correctly...?

And how does your book define "all work needed"?

Please reply with clear and specific answers. Thank you.

Eliz.

 

[Guest]

1. vertical asymptotes
2.maximum and minimum values
3.points of inflection