Counting Principle

Pingu

Junior Member
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Dec 22, 2005
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The question is: How many even two-digit whole numberscan be made using the digits 1,2,3,4,5,6,7, and 8. Repetitions are not allowed.
 
G'day, Pingu.

An even number must end with an even digit. Try writing down all the possibilities for a number ending with 2 from the given digits. Can you see a pattern emerging?
 
Hello, Pingu!

How many even two-digit whole numbers can be made using the digits 1,2,3,4,5,6,7, and 8.
Repetitions are not allowed.
The units-digit must be even; there are four choices: {2,4,6,8}.

The tens-digit can be any of the other seven digits.

Answer: \(\displaystyle \,4\,\times\,7\:=\:28\) possible even two-digit numbers.
 
the unit digits can be even or odd.
for odd, there are 4 choices. [1,3,5,7]
therefore, odd would have 4 choices as well and it has to be even [2,4,6,8]

for unit digits to be even, there are 4 choices. [2,4,6,8]
however, since repetitions are not allowed, tens digits only have 3 choices.

therefore...
4x4 + 4x3 = 16 + 12 = 28
 
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