Multiply (x+12)(x-3) Factor xy+yz Factor completely 2(x-3) -a(x-3)
B BChick New member Joined May 17, 2007 Messages 1 May 19, 2007 #1 Multiply (x+12)(x-3) Factor xy+yz Factor completely 2(x-3) -a(x-3)
M morson Full Member Joined Apr 12, 2007 Messages 263 May 19, 2007 #2 Make use of the distributive laws, true for all real values of a, b, c and d: (a + b)(c + d) = ac + ad + bc + bd a(b + c) = ab + ac Or, conversely, ab + ac = a(b + c) [which should help you in your 2nd question]
Make use of the distributive laws, true for all real values of a, b, c and d: (a + b)(c + d) = ac + ad + bc + bd a(b + c) = ab + ac Or, conversely, ab + ac = a(b + c) [which should help you in your 2nd question]
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 May 19, 2007 #3 Where were you during math classes, Chickadee ?