cot(α)

[mova]

Can you please help me with this?

If α is located in the first quadrant,
Let u=sinαcosα and v=cotα.
Show v as a function of u.

 

[Deleted member 4993]

Can you please help me with this?

If α is located in the first quadrant,
Let u=sinαcosα and v=cotα.
Show v as a function of u.

v / u = ?

Any relation with 'v' come into mind?

 

[Steven G]

Draw a right triangle and get your hands dirty! Suppose the vertices are A, B and C. Further suppose α is opposite angle A, [math]\beta[/math] is opposite and B and C is the hypotenuse.

The v = ? and u =?
Now can you write v as a function of u

On this forum we do not solve problems for students. We prefer students to solve their own problems with help from forum members. In the future please show us your work so that we know where you are stuck. Please post back with your work so that we can check it and if necessary guide you.

 

[Dr.Peterson]

Draw a right triangle and get your hands dirty! Suppose the vertices are A, B and C. Further suppose α is opposite angle A, [math]\beta[/math] is opposite and B and C is the hypotenuse.

The v = ? and u =?
Now can you write v as a function of u

I don't think you meant that. [MATH]\alpha[/MATH] is angle A!

If α is located in the first quadrant,
Let u=sinαcosα and v=cotα.
Show v as a function of u.

My approach is to find expressions for uv and u/v, which have an interesting relationship.

It will be easy to write u as a function of v; v will not be a function of u, though you can write it as two functions.

 

[Deleted member 4993]

Can you please help me with this?

If α is located in the first quadrant,
Let u=sinαcosα and v=cotα.
Show v as a function of u.

v/u = cosec²(α)

cosec²(α) = 1 + cot²(α)

continue......