xceler8ari1984
New member
- Joined
- Nov 12, 2006
- Messages
- 7
The value of a computer t years after purchase is given by v(t) = 2000e^(-0.35t)
a) What is the value of the computer after 3 years?
b) At what rate is the computer's value depreciating after 3 years?
c) When will the value of the computer be $800?
Ok, this is what I have figured out
a) v(t) = (2000)e^(-0.35(3))
. . .= (2000)e^(-1.05)
. . .= $699.87
b) v'(3) = -0.35*v(t)
. . .= -0.35(699.87) = -244.95
c) 800 = (2000)e^(-0.35t)
. . .800/2000 = e^(-0.35t)
. . .ln(8/20) = -0.35t
. . .0.916 = -0.35t
. . .t = 2.61
Is this correct?
a) What is the value of the computer after 3 years?
b) At what rate is the computer's value depreciating after 3 years?
c) When will the value of the computer be $800?
Ok, this is what I have figured out
a) v(t) = (2000)e^(-0.35(3))
. . .= (2000)e^(-1.05)
. . .= $699.87
b) v'(3) = -0.35*v(t)
. . .= -0.35(699.87) = -244.95
c) 800 = (2000)e^(-0.35t)
. . .800/2000 = e^(-0.35t)
. . .ln(8/20) = -0.35t
. . .0.916 = -0.35t
. . .t = 2.61
Is this correct?