converting into an algebraic form sec(arctan4x) would it be sec(4/(1+(3x)^2)
I icyhot2590 New member Joined Mar 18, 2007 Messages 22 Mar 21, 2007 #1 converting into an algebraic form sec(arctan4x) would it be sec(4/(1+(3x)^2)
skeeter Elite Member Joined Dec 15, 2005 Messages 3,216 Mar 21, 2007 #2 Re: sec(arctan4x) icyhot2590 said: converting into an algebraic form sec(arctan4x) would it be sec(4/(1+(3x)^2) Click to expand... no. let y = arctan(4x) ... then tan(y) = 4x/1 = opposite/adjacent using Pythagoras ... hypotenuse = sqrt(1 + 16x<sup>2</sup>) sec(y) = hypotenuse/adjacent = sqrt(1 + 16x<sup>2</sup>)
Re: sec(arctan4x) icyhot2590 said: converting into an algebraic form sec(arctan4x) would it be sec(4/(1+(3x)^2) Click to expand... no. let y = arctan(4x) ... then tan(y) = 4x/1 = opposite/adjacent using Pythagoras ... hypotenuse = sqrt(1 + 16x<sup>2</sup>) sec(y) = hypotenuse/adjacent = sqrt(1 + 16x<sup>2</sup>)
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Mar 21, 2007 #3 icyhot2590 said: would it be sec(4/(1+(3x)^2) Click to expand... How did you arrive at this answer? Please reply showing all of your work and reasoning. Thank you. Eliz.
icyhot2590 said: would it be sec(4/(1+(3x)^2) Click to expand... How did you arrive at this answer? Please reply showing all of your work and reasoning. Thank you. Eliz.