Convert r = 2 sin (theta) into cartesian form:
It looks simple, but I can't do it
Here's what I did:
root(x^2 + y^2) = 2y/r, since y = r sin(theta)
So: 2y = root(x^2 + y^2) * root(x^2 + y^2)
2y = x^2 + y^2
and what now??
I know from calculator that the answer should be x^2 +(y-1)^2 = 1 with centre at (0,1).
It looks simple, but I can't do it
Here's what I did:
root(x^2 + y^2) = 2y/r, since y = r sin(theta)
So: 2y = root(x^2 + y^2) * root(x^2 + y^2)
2y = x^2 + y^2
and what now??
I know from calculator that the answer should be x^2 +(y-1)^2 = 1 with centre at (0,1).