T Tbertino New member Joined Jul 15, 2006 Messages 2 Jul 15, 2006 #1 I'm having a brain fart trying to go from log to exponential I've solved for the log equation which is: 158.574-42.877lnx I can't make my brain convert this to exponent form. :?
I'm having a brain fart trying to go from log to exponential I've solved for the log equation which is: 158.574-42.877lnx I can't make my brain convert this to exponent form. :?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Jul 16, 2006 #2 Hello tbertino: \(\displaystyle \L\\158.574=42.877ln(x)\) Divide both sides by 42.877: \(\displaystyle \L\\3.69834643282=ln(x)\) e of both sides: \(\displaystyle \L\\e^{3.69834643282}=e^{ln(x)}\) \(\displaystyle \L\\e^{3.69834643282}=x\) \(\displaystyle \L\\x\approx{40.38}\)
Hello tbertino: \(\displaystyle \L\\158.574=42.877ln(x)\) Divide both sides by 42.877: \(\displaystyle \L\\3.69834643282=ln(x)\) e of both sides: \(\displaystyle \L\\e^{3.69834643282}=e^{ln(x)}\) \(\displaystyle \L\\e^{3.69834643282}=x\) \(\displaystyle \L\\x\approx{40.38}\)
T Tbertino New member Joined Jul 15, 2006 Messages 2 Jul 16, 2006 #3 The back of the book shows the answer to the problem as: 123.238(0.935550^x) How did they get there from 158.574-42.877lnx? Thanks! Tamara
The back of the book shows the answer to the problem as: 123.238(0.935550^x) How did they get there from 158.574-42.877lnx? Thanks! Tamara
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Jul 16, 2006 #4 I've solved for the log equation which is: 158.574-42.877lnx Click to expand... Got news for you ... 158.574-42.877lnx is not an "equation". Maybe your "solution" is in error. Try posting the complete problem, from whence it started.
I've solved for the log equation which is: 158.574-42.877lnx Click to expand... Got news for you ... 158.574-42.877lnx is not an "equation". Maybe your "solution" is in error. Try posting the complete problem, from whence it started.