convert a log equation to an exponential equation

Tbertino

New member
Joined
Jul 15, 2006
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2
I'm having a brain fart trying to go from log to exponential
I've solved for the log equation which is:
158.574-42.877lnx

I can't make my brain convert this to exponent form.

:?
 
Hello tbertino:

\(\displaystyle \L\\158.574=42.877ln(x)\)

Divide both sides by 42.877:

\(\displaystyle \L\\3.69834643282=ln(x)\)

e of both sides:

\(\displaystyle \L\\e^{3.69834643282}=e^{ln(x)}\)

\(\displaystyle \L\\e^{3.69834643282}=x\)

\(\displaystyle \L\\x\approx{40.38}\)
 
The back of the book shows the answer to the problem as:
123.238(0.935550^x)
How did they get there from 158.574-42.877lnx?
Thanks!
Tamara
 
I've solved for the log equation which is:
158.574-42.877lnx

Got news for you ... 158.574-42.877lnx is not an "equation".

Maybe your "solution" is in error.

Try posting the complete problem, from whence it started.
 
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