convert a continued fraction into a normal fraction

enoimreh7

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Joined
Nov 14, 2017
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34
Hello!

Could you please help me converting the following continued fraction into a normal fraction, please? My calculator isn't goog enough, and I don't know how to solve it without.
I don't know how to write it like a fraction, so I write it like a term:

1+1:(2+1:(2+1:(2+1:(2+1:(2+1:(2+1:2))))))

I tried to do it "manual": 2+1:2=2.5 ; 2+1:2.5=2.4 ; 2+1:2.4=2.4166... ; and so on... But then, after a time, my calculator says it would be 0, but that's definitely wrong.
And then, I have to salve that term, too, but with my calculator, it's impossible:

(
b4afc1e27d418021bf10898eb44a7f5f315735ff
-(1+1:(2+1:(2+1:(2+1:(2+1:(2+1:(2+1:2)))))))):
b4afc1e27d418021bf10898eb44a7f5f315735ff
·100

Could you help me with this one, too, please?
Thank you very much!

Yours,
Enoimreh
 
Last edited:
Could you please help me converting the following continued fraction into a normal fraction, please? My calculator isn't good enough, and I don't know how to solve it without.
I don't know how to write it like a fraction, so I write it like a term:

1+1: (2+1: (2+1: (2+1: (2+1: (2+1: (2+1:2))))))

I tried to do it "manual": 2+1:2=2.5 ; 2+1:2.5=2.4 ; 2+1:2.4=2.4166... ; and so on... But then, after a time, my calculator says it would be 0, but that's definitely wrong.
And then, I have to salve that term, too, but with my calculator, it's impossible:

(
b4afc1e27d418021bf10898eb44a7f5f315735ff
-(1+1
: (2+1: (2+1: (2+1: (2+1: (2+1: (2+1:2)))))))):
b4afc1e27d418021bf10898eb44a7f5f315735ff
·100

Could you help me with this one, too, please?


Let's start with just the first.

I would do it manually, using fractions. Start, as you did, in the middle:

2 + 1/2 = 4/2 + 1/2 = 5/2

2 + 1/(5/2) = 2 + 2/5 = 10/5 + 2/5 = 12/5

and so on.

Can you finish? Note that the process amounts to alternately taking a reciprocal, then adding 2. You can do it easily on a calculator this way, especially if it has a reciprocal button.
 
Hello Dr. Peterson!

I am very surprised that my calculator worked this time. Before he has always said that there would have been an error. Now he brought out this:

2+1:(2+1:(2+1:(2+1:(2+1:2))))=169:70
2+1:(169:70)=408:169
1+1:
(408:169)=577:408

(
b4afc1e27d418021bf10898eb44a7f5f315735ff
-577:408):
b4afc1e27d418021bf10898eb44a7f5f315735ff
x 100 =-1,50182509x10-4


Is that all right?
Thank you very much for enspireing me to try it again.

Yours,
Enoimreh
 
Hello Dr. Peterson!

I am very surprised that my calculator worked this time. Before he has always said that there would have been an error. Now he brought out this:

2+1: (2+1: (2+1: (2+1: (2+1:2))))=169:70
2+1: (169:70)=408:169
1+1:
(408:169)=577:408

(
b4afc1e27d418021bf10898eb44a7f5f315735ff
-577:408):
b4afc1e27d418021bf10898eb44a7f5f315735ff
x 100 =-1,50182509x10-4


Is that all right?
Thank you very much for enspireing me to try it again.


Yes, that is correct. I guessed that you made some little error in the long calculation, and either redoing it, or using a simpler approach, would get you past that.

The result shows, of course, that this continued fraction is a very good approximation to the square root of 2. The decimal value of 577/408 is 1.414215686..., while sqrt(2) is 1.414213562... .

Incidentally, I did my calculations even faster, using a spreadsheet to do each repetition for me.
 
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