Convergence math task? (urgent!!!) D:

[Fscene8]

Please step by step.
If you could PLEASE write down on paper then scan or take picture.
Thanks in advance.



Forgive me for not learning stuff on time and not doing homework D:

 

[DrPhil]

Please step by step.
If you could PLEASE write down on paper then scan or take picture.
Thanks in advance.

\(\displaystyle \displaystyle \sum \dfrac{2^{n-1}}{n^n}\)

Forgive me for not learning stuff on time and not doing homework D:

Please read the post "Read before Posting!!"

Without seeing your work, we don't know where you need help. If you write 2^(n-1) as 2^n × 2^(-1), then there is a factor of (1/2) that you can take outside the sum:

\(\displaystyle \displaystyle \dfrac{1}{2}\ \sum \dfrac{2^n}{n^n}\)

Does that look more like a problem you have probably already done? What rules do you know?