Convergence/ Divergence

[Lolauren1]

sigma k=0 to infinity (sin(pi/6))^k is...
A)1
B)2
C)1/(1-sq. root of 3/2)
D) sq. root of 3/2/(1- sq. root of 3/2)
E) does not converge

 

[tkhunny]

\(\displaystyle \sin\left(\frac{\pi}{6}\right) = 1/2\)

Doesn't that make your series Geometric?

That should be easy enough.