Conics

[KyleP]

I am having some problems with conics and figuring out equations and characteristics of each conic. If someone is familiar with this, I have a few problems I would like to know answers to.

 

[galactus]

Post them. Let's have a look.

 

[KyleP]

On these, we were supposed to identify the characteristics (vertices, foci, center, etc.), and then graph each of them.

16x^2 + 16y^2 - 16x + 24y - 3 = 0
I got it into the form (x-1/2)^2 + (y+3/4)^2 = 1 however, I am not sure that this is correct.

4x^2 + y^2 - 16x + 15 = 0
I got this into the equation (x-2)/1 + y^2/4 = 1 I believe this is correct, but I wasn't sure how to find the foci.

Those are just a couple for now. I do have a few more, if someone gets these figured out. Thanks!

 

[stapel]

I do have a few more, if someone gets these figured out.

Just to clarify: Legitimate tutors don't "do" students' work for them. If that's what you're looking for, then I'm afraid this may not be the right site for you. :shock:

On the other hand, if you're saying that you missed the lectures on this topic, the book isn't making sense, the classnotes aren't helping, and you're needing lesson links so you can learn, then we can help! :wink:

Note: In order for us to be able to check your work, you really do need to show it. We can't find errors if all you give us is the final results.

Thank you!

Eliz.

:arrow: P.S. Welcome to FreeMathHelp!

 

[KyleP]

no, I wasn't trying to cheat or just send my work over to all of you to do. I have spent several hours looking over my notes, other homework from this chapter, and other web sites, and just can not understand how to solve the equations. If I do need to show you my step by step work, I would be glad to do that.

Thanks.

 

[Deleted member 4993]

On these, we were supposed to identify the characteristics (vertices, foci, center, etc.), and then graph each of them.

16x^2 + 16y^2 - 16x + 24y - 3 = 0
I got it into the form (x-1/2)^2 + (y+3/4)^2 = 1


x^2 - x + 1/4 + y^2 + 3/2 * y + 9/16 - 3/16 - 1/4 - 9/16 = 0

(x - 1/2)^2 + (y + 3/4)^2 = 16/16

So you are correct

however, I am not sure that this is correct.

4x^2 + y^2 - 16x + 15 = 0

x^2 - 4x + 4 + (y/2)^2 + 15/4 - 4 = 0

(x-2)^2 + y^2/4 = (1/2)^2

(x-2)^2 / (1/2)^2 + y^2/(1)^2 = 1

To find the location of focus - you need to find the eccentricity of the ellipse.

Do a google search to find coordinates of focii an ellipse.

I got this into the equation (x-2)/1 + y^2/4 = 1 I believe this is correct, but I wasn't sure how to find the foci.

Those are just a couple for now. I do have a few more, if someone gets these figured out. Thanks!