The question is asking to find the standard form of the equation of the hyperbola with the given characteristics:
Verticies: (-2,1), (2,1)
Foci: (-3,1), (3,1)
using the c^2=A^2 + B^2
I find that a = 2(verticies) and c = 3(foci)
so b= ?5
Plugging everything back in the standard equation I got
((x^2)/4) - (((y-1)^2)/25) = 1
Can someone please confirm that my answer is correct. Thanks!
Verticies: (-2,1), (2,1)
Foci: (-3,1), (3,1)
using the c^2=A^2 + B^2
I find that a = 2(verticies) and c = 3(foci)
so b= ?5
Plugging everything back in the standard equation I got
((x^2)/4) - (((y-1)^2)/25) = 1
Can someone please confirm that my answer is correct. Thanks!
