Confused: triangle CDE, CD=3y < DE=30, CE=45,....

[Cinnamon]

IN triangle CDE, CD=3y< DE =30 and CE=45 determine the range of possible values for y.

 

[Denis]

Assuming integers, and given lengths of sides a and b of a triangle,
third side c = abs(a-b)+1 to a+b-1

Make your 3rd side 3y and you should have no problems.

 

[skeeter]

IN triangle CDE, CD=3y< DE =30 and CE=45 determine the range of possible values for y.

the sum of any two sides of a triangle must be greater than the length of the 3rd side ...

|CD| + |DE| > |CE|
3y + 30 > 45
3y > 15
y > 5

you were also given that |CD| = 3y < 30 ... so, y < 10

what is the range of possible values for y?