Well the problem is this
1) Find a polynomial function p(x) that computes the volume of the box in terms of x. What is the degree of p?
2) Find a polynomial function q(x) that computes the exposed surface area of the closed box in terms of x. What is the degree of q? What are the explicit dimensions if the exposed surface of the area is 600 square inches?
What I did:
Length = 20 - 2x
Width = (50 - 2x)/2 = 25 - x
Height = x
Volume of a Rectangle = a b c = (20-2x) * (25-x) * x = 500x - 70x^2 - 2x^3
Degree = 3
Just curious, why would it be -2x for length and width
Also how did width get all over 2?
(I had some help to start earlier ago)
2ab + 2bc + 2ac right?
a = 20-2x
b = 25-x
c = x
2(20-2x)(25-x) + 2(25-x)(x) + 2(20-2x)(2x)
=2(500-20x-50x+2x^2) + 2(25x+x^2) + 2(40x-4x^2)
=2(500-70x+2x^2) + 2(25x+x^2) + 2(40x-4x^2)
=1000-140x+4x^2+50x+2x^2+80x-8x^2
=1000-60x-2x^2
Though I think I messed up, it's suppose to be -50x instead of -60x, but I don't know how did I do it wrong
And how would you do "What are the explicit dimensions if the exposed surface of the area is 600 square inches?"
SOLVED
Yeah, I got what I did wrong and found out what it means for the 600 part
Thanks for all your help
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