For example:
f(x)=2x2+5x-3
So I did the tic tac toe method which the teacher taught us
ax2 c ax2c
Which then I plug it in
2x2 -3 -6x2
2x -1 -2x
1x 3 3x
Then circle diagonally at the 2x2 square at the bottom left
Which I get (2x+3)(1x-1)
Which was apparently wrong
It's suppose to be
2x2 -3 -6x2
2x 3 6x
1x -1 -1x
Therefore I get (2x-1)(1x+3)
My zeroes would then be (1/2) and -3
I'm kind of confuse what made the first one wrong
And is there another way to factor? Cause you would have to find a lot of multiples that would fit.
f(x)=2x2+5x-3
So I did the tic tac toe method which the teacher taught us
ax2 c ax2c
Which then I plug it in
2x2 -3 -6x2
2x -1 -2x
1x 3 3x
Then circle diagonally at the 2x2 square at the bottom left
Which I get (2x+3)(1x-1)
Which was apparently wrong
It's suppose to be
2x2 -3 -6x2
2x 3 6x
1x -1 -1x
Therefore I get (2x-1)(1x+3)
My zeroes would then be (1/2) and -3
I'm kind of confuse what made the first one wrong
And is there another way to factor? Cause you would have to find a lot of multiples that would fit.