peggyskold
New member
- Joined
- Jan 30, 2009
- Messages
- 24
Can someone please help me to understand this rule for dependent events P(A) P(A/B) what are the math operations to do this? I know I am just missing something here but I need to grasp how to do this.
P(B/A) I know it is is supposed to be P(B) the probability of event B, P(A) the probability of event a and then what do you to to figure out P(B/A) ? Is this event B divided by event A? NO....don't get it.
for instance I can do this type (I think)
Water Orange juice Cola
Under 21 years 40 25 20
21 – 40 years 35 20 30
Over 40 years 20 30 35
If one of the 255 subjects is randomly chosen, find the probability that the person drinks cola given they are under 21.
So the total number of those who drink cola is 85 and the total number of those who are under 21 is 20. So I divide 20/85 to get 0.235. (I think this is right)
On this one, even though I am looking at the solution of this one I can't quite understand it;
In the general populaton one woman in eight will develop breast cancer. Research shows that 1 woman in 600 carries a BRCA gene. Eight out of 10 women with this mutation develop breast cancer.
Find the probability that a randomly selected woman will develop breast cancer given that she has a mutation of the BRCA gene.
The solution is P(B) = 1/8, P(A) = 1/600, and P(B/A) = 8/10. So P(B/A)=8/10 = 0.8
What operations did they do to get the 8/10?
P(B/A) I know it is is supposed to be P(B) the probability of event B, P(A) the probability of event a and then what do you to to figure out P(B/A) ? Is this event B divided by event A? NO....don't get it.
for instance I can do this type (I think)
Water Orange juice Cola
Under 21 years 40 25 20
21 – 40 years 35 20 30
Over 40 years 20 30 35
If one of the 255 subjects is randomly chosen, find the probability that the person drinks cola given they are under 21.
So the total number of those who drink cola is 85 and the total number of those who are under 21 is 20. So I divide 20/85 to get 0.235. (I think this is right)
On this one, even though I am looking at the solution of this one I can't quite understand it;
In the general populaton one woman in eight will develop breast cancer. Research shows that 1 woman in 600 carries a BRCA gene. Eight out of 10 women with this mutation develop breast cancer.
Find the probability that a randomly selected woman will develop breast cancer given that she has a mutation of the BRCA gene.
The solution is P(B) = 1/8, P(A) = 1/600, and P(B/A) = 8/10. So P(B/A)=8/10 = 0.8
What operations did they do to get the 8/10?