tworitdash
New member
- Joined
- Aug 12, 2022
- Messages
- 10
I have the following function
[math]x(k) = \sum_{m}^{M} e^{i(U_m k + \beta_m)}[/math]
Where
[math]i = \sqrt{-1}[/math]
And [imath] k [/imath] is an integer.
The [imath] U_m [/imath] values come from a normal distribution and the [imath]\beta_m [/imath] values come from a uniform distribution.
[math]U_m \sim \mathcal{N}(\mu, \sigma^2)[/math][math]\beta_m \sim \mathcal{U}(0, 2 \pi)[/math]
I want to know the conditional probability of both parameters [imath]\mu [/imath] and [imath]\sigma^2 [/imath] with each other.
Something like [imath]p(\mu|x, \sigma^2) [/imath] and [imath]p(\sigma^2|x, \mu) [/imath]
I have seen how people do it when [imath]x [/imath] is a random number following a specific distribution. However, how to deal with this sum. I have attempted finding the distribution of the sum inside the function [imath]x [/imath], but I am almost unsuccessful. It can be found after the question. I know with central limit theorem (when [imath]M [/imath] is large and [imath]\sigma [/imath] is large), the distribution of [imath]x [/imath] is a Gaussian distribution with mean [imath]0 [/imath] and standard deviation [imath]\sqrt{M/2} [/imath] for both the real and the imaginary parts. However, how to find the statistics of [imath]x [/imath] when [imath]M [/imath] is still large but with not so big [imath]\sigma [/imath]. So there are three cases:
1) [imath]M [/imath] large and [imath]\sigma [/imath] large - x becomes Gaussian with [imath]\mu_x = 0 [/imath] and [imath]\sigma_x = \sqrt{M/2} [/imath] for both real and imaginary
2) [imath]M [/imath] large and [imath]\sigma -> 0 [/imath], the distribution of [imath]x [/imath] becomes [imath]\delta(1) [/imath].
3) [imath]M [/imath] large but [imath]\sigma [/imath] reasonable - I want the distribution of [imath]x [/imath] as a function of [imath]\sigma [/imath] (and possibly [imath]\mu [/imath]).
Or, am I attempting the question in a wrong way? The original problem is to estimate [imath]\mu [/imath] and [imath]\sigma [/imath] when some realizations of[imath]x [/imath] is available. Is it worth having an expression of the distribution of both real and imaginary parts of[imath]x [/imath] when[imath]M [/imath] is large in terms of [imath]\mu [/imath] and [imath]\sigma [/imath] ? I was thinking of it because, in that case the conditional probabilities would be easier to find and any iterative technique can be used to estimate [imath]\mu[/imath] and [imath]\sigma [/imath].
What I have tried so far:
If I write the original model like this:
[math]x(k) = \sum_m A_m + i \Gamma_m[/math]
I have the distribution of [imath] \alpha [/imath] and [imath] \gamma [/imath].
They look like the following;
[math]f_A(\alpha) = \sum_{n = -\infty}^{+\infty} \frac{1}{\sqrt{1 - \alpha^2}} \Big( f_Y(2(n+1)\pi - \cos^{-1}(\alpha)) - f_Y(2(n)\pi + \cos^{-1}(\alpha)) \Big)[/math]
[math]f_\Gamma(\gamma) = \sum_{n = -\infty}^{+\infty} \frac{1}{\sqrt{1 - \alpha^2}} \Big( f_Y(2(n)\pi + \sin^{-1}(\alpha)) - f_Y((2n-1)\pi - \sin^{-1}(\alpha)) \Big)[/math]
Where [imath] f_Y(y) [/imath] is the density function of the random variable[imath] Y = U k + \beta[/imath] , which is
[math] f_Y(y) = \frac{1}{4\pi} \Big[ erf\Big( \frac{k \mu -y + 2 \pi}{\sqrt{2} k \sigma } \Big) - erf\Big( \frac{k \mu -y}{\sqrt{2} k \sigma } \Big) \Big][/math]
[math]x(k) = \sum_{m}^{M} e^{i(U_m k + \beta_m)}[/math]
Where
[math]i = \sqrt{-1}[/math]
And [imath] k [/imath] is an integer.
The [imath] U_m [/imath] values come from a normal distribution and the [imath]\beta_m [/imath] values come from a uniform distribution.
[math]U_m \sim \mathcal{N}(\mu, \sigma^2)[/math][math]\beta_m \sim \mathcal{U}(0, 2 \pi)[/math]
I want to know the conditional probability of both parameters [imath]\mu [/imath] and [imath]\sigma^2 [/imath] with each other.
Something like [imath]p(\mu|x, \sigma^2) [/imath] and [imath]p(\sigma^2|x, \mu) [/imath]
I have seen how people do it when [imath]x [/imath] is a random number following a specific distribution. However, how to deal with this sum. I have attempted finding the distribution of the sum inside the function [imath]x [/imath], but I am almost unsuccessful. It can be found after the question. I know with central limit theorem (when [imath]M [/imath] is large and [imath]\sigma [/imath] is large), the distribution of [imath]x [/imath] is a Gaussian distribution with mean [imath]0 [/imath] and standard deviation [imath]\sqrt{M/2} [/imath] for both the real and the imaginary parts. However, how to find the statistics of [imath]x [/imath] when [imath]M [/imath] is still large but with not so big [imath]\sigma [/imath]. So there are three cases:
1) [imath]M [/imath] large and [imath]\sigma [/imath] large - x becomes Gaussian with [imath]\mu_x = 0 [/imath] and [imath]\sigma_x = \sqrt{M/2} [/imath] for both real and imaginary
2) [imath]M [/imath] large and [imath]\sigma -> 0 [/imath], the distribution of [imath]x [/imath] becomes [imath]\delta(1) [/imath].
3) [imath]M [/imath] large but [imath]\sigma [/imath] reasonable - I want the distribution of [imath]x [/imath] as a function of [imath]\sigma [/imath] (and possibly [imath]\mu [/imath]).
Or, am I attempting the question in a wrong way? The original problem is to estimate [imath]\mu [/imath] and [imath]\sigma [/imath] when some realizations of[imath]x [/imath] is available. Is it worth having an expression of the distribution of both real and imaginary parts of[imath]x [/imath] when[imath]M [/imath] is large in terms of [imath]\mu [/imath] and [imath]\sigma [/imath] ? I was thinking of it because, in that case the conditional probabilities would be easier to find and any iterative technique can be used to estimate [imath]\mu[/imath] and [imath]\sigma [/imath].
What I have tried so far:
If I write the original model like this:
[math]x(k) = \sum_m A_m + i \Gamma_m[/math]
I have the distribution of [imath] \alpha [/imath] and [imath] \gamma [/imath].
They look like the following;
[math]f_A(\alpha) = \sum_{n = -\infty}^{+\infty} \frac{1}{\sqrt{1 - \alpha^2}} \Big( f_Y(2(n+1)\pi - \cos^{-1}(\alpha)) - f_Y(2(n)\pi + \cos^{-1}(\alpha)) \Big)[/math]
[math]f_\Gamma(\gamma) = \sum_{n = -\infty}^{+\infty} \frac{1}{\sqrt{1 - \alpha^2}} \Big( f_Y(2(n)\pi + \sin^{-1}(\alpha)) - f_Y((2n-1)\pi - \sin^{-1}(\alpha)) \Big)[/math]
Where [imath] f_Y(y) [/imath] is the density function of the random variable[imath] Y = U k + \beta[/imath] , which is
[math] f_Y(y) = \frac{1}{4\pi} \Big[ erf\Big( \frac{k \mu -y + 2 \pi}{\sqrt{2} k \sigma } \Big) - erf\Big( \frac{k \mu -y}{\sqrt{2} k \sigma } \Big) \Big][/math]
Last edited: