condensing a log

[pinkcalculator]

I know that subtraction becomes division, but I'm not sure how this would work out because it's divided twice.

3logx-logy-5logz

(logx cubed/log y)/logz to the fifth power??

 

[Deleted member 4993]

I know that subtraction becomes division, but I'm not sure how this would work out because it's divided twice.



(logx cubed/log y)/logz to the fifth power?? ..... not quite

\(\displaystyle Log(A) - Log(B) = Log\left (\frac{A}{B}\right )\)

Spoiler: :l18af9gq

\(\displaystyle 3logx-logy-5logz = Log\left (\frac{x^3}{z^5\cdot y}\right )\)[/spoiler:l18af9gq]