Tclements3
New member
- Joined
- Apr 3, 2012
- Messages
- 3
Determine where the following function is concave up:
3x^5-5x^4-120x^3-430x+1
I know that the first derivitave is 15x^4-20x^3-360x^2-430
and the second derivitave is 60x^3-60x^2-720x = 60x(x^2-x-12) = 60x(x+3)(x-4)
That's where I get stuck. The answer key says it is concave up in [-2,0]U[3,inf) but I cannot figure out how to get there. Any help is appreciated!
3x^5-5x^4-120x^3-430x+1
I know that the first derivitave is 15x^4-20x^3-360x^2-430
and the second derivitave is 60x^3-60x^2-720x = 60x(x^2-x-12) = 60x(x+3)(x-4)
That's where I get stuck. The answer key says it is concave up in [-2,0]U[3,inf) but I cannot figure out how to get there. Any help is appreciated!