Computing Limits at Infinity Part II

Hckyplayer8

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Compute the lim as x--> infinity of [5x3 + 4x2 + 2] / [x4-8x3-7x2+4]

The first step is to divide both sides of the fraction by the highest power which is x4.

The result is [5/x + 4/x2 + 2/x4] / [1 - 8/x - 7/x2 + 4/x4]

Since the only constant is in the denominator, I should be looking at an end value of 0/1 for my answer.
 
Compute the lim as x--> infinity of [5x3 + 4x2 + 2] / [x4-8x3-7x2+4]

The first step is to divide both sides of the fraction by the highest power which is x4.

The result is [5/x + 4/x2 + 2/x4] / [1 - 8/x - 7/x2 + 4/x4]

Since the only constant is in the denominator, I should be looking at an end value of 0/1 for my answer.
Yes which is just 0.
 
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