Compound Interest

cruz52

New member
Joined
Sep 12, 2010
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4
How long will it take money to double if it is invested at 8% compound semiannually?


I know you have to use the formula 2p = A = P(1+ i)^mt

I did the steps 2(1 + .08/2)^2t

Than 2 = (1.04) ^2t

ln2 = 2tln(1.04) = t = ln/2ln(1.04) ... Every time I solve it out I get a decimal answer can anyone tell me what I am doing wrong?
 
cruz52 said:
How long will it take money to double if it is invested at 8% compound semiannually?


I know you have to use the formula 2p = A = P(1+ i)^mt

I did the steps 2(1 + .08/2)^2t

Than 2 = (1.04) ^2t

ln2 = 2tln(1.04) = t = ln/2ln(1.04) ... Every time I solve it out I get a decimal answer can anyone tell me what I am doing wrong?

2P = P(1+0.082)2t\displaystyle 2*P \ = \ P*(1 + \frac{0.08}{2})^{2*t}

2 = (1+0.04)2t\displaystyle 2 \ = \ (1 + 0.04)^{2*t}

ln(2) = 2tln(1+0.04)\displaystyle ln(2) \ = \ 2*t * ln(1 + 0.04)

t = ln(2)2ln(1.04)\displaystyle t \ = \ \frac{ln(2)}{2*ln(1.04)}

You are here without any troble

t = 0.6931471812  0.039220713\displaystyle t \ = \ \frac{0.693147181}{2 \ * \ 0.039220713}

t = 0.6931471810.078441426\displaystyle t \ = \ \frac{0.693147181}{0.078441426}

t = 8.836493843 years\displaystyle t \ = \ 8.836493843 \ years

This is correct - because "rule of 72" tells you that the answer should be ~9 years

You must be making some "punching" error.....
 
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