composition functions - treatment 3

logistic_guy

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here is the question

Find the compositions fg\displaystyle f \circ g and gf\displaystyle g \circ f, and identify their respective domains.

3. f(x)=1x,  g(x)=x3+4\displaystyle f(x) = \frac{1}{x}, \ \ g(x) = x^3 + 4


my attemb
fg=f(g(x))=1x3+4\displaystyle f \circ g = f(g(x)) = \frac{1}{x^3 + 4}
Domain: x43\displaystyle x \neq \sqrt[3]{-4}

gf=g(f(x))=(1x)3+4=1x3+4\displaystyle g \circ f = g(f(x)) = (\frac{1}{x})^3 + 4 = \frac{1}{x^3} + 4
Domain: x0\displaystyle x \neq 0

is my analize correct?😣
 
here is the question

Find the compositions fg\displaystyle f \circ g and gf\displaystyle g \circ f, and identify their respective domains.

3. f(x)=1x,  g(x)=x3+4\displaystyle f(x) = \frac{1}{x}, \ \ g(x) = x^3 + 4


my attemb
fg=f(g(x))=1x3+4\displaystyle f \circ g = f(g(x)) = \frac{1}{x^3 + 4}
Domain: x43\displaystyle x \neq \sqrt[3]{-4}

gf=g(f(x))=(1x)3+4=1x3+4\displaystyle g \circ f = g(f(x)) = (\frac{1}{x})^3 + 4 = \frac{1}{x^3} + 4
Domain: x0\displaystyle x \neq 0

is my analize correct?😣
You tell us. Are there any x's that would make any of these expressions
something0\dfrac{\text{something}}{0},

or
put a negative under a square root?

-Dan
 
I'm asking you to check your own work....

Those two are not the only criteria to worry about but they cover some 90% of what you will see.

-Dan
i'm not understand what you're trying to say☹️
can you point out where my mistake?
 
There is no mistake. These are elementary enough that I'm expecting you to check your own work now.

-Dan
 
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