composition functions - treatment 1

logistic_guy

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Apr 17, 2024
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here is the question

Find the compositions fg\displaystyle f \circ g and gf\displaystyle g \circ f, and identify their respective domains.

1. f(x)=x+1,  g(x)=x3\displaystyle f(x) = x + 1, \ \ g(x) = \sqrt{x - 3}


my attemb
recently i take rigorous treatment in algebra and i master 99%\displaystyle 99\%
some fragments remain unmastered, particulary the domain of composition function
most of the time, i get the domain wrong
so i'll make 6\displaystyle 6 treatments to hope finally i overcome this tiny issue

fg=f(g(x))=x3+1\displaystyle f \circ g = f(g(x)) = \sqrt{x - 3} + 1
Domain: x3\displaystyle x \geq 3

gf=g(f(x))=x+13=x2\displaystyle g \circ f = g(f(x)) = \sqrt{x + 1 - 3} = \sqrt{x - 2}
Domain: x2\displaystyle x \geq 2

is my analize correct?😣
 
here is the question

Find the compositions fg\displaystyle f \circ g and gf\displaystyle g \circ f, and identify their respective domains.

1. f(x)=x+1,  g(x)=x3\displaystyle f(x) = x + 1, \ \ g(x) = \sqrt{x - 3}


my attemb
recently i take rigorous treatment in algebra and i master 99%\displaystyle 99\%
some fragments remain unmastered, particulary the domain of composition function
most of the time, i get the domain wrong
so i'll make 6\displaystyle 6 treatments to hope finally i overcome this tiny issue

fg=f(g(x))=x3+1\displaystyle f \circ g = f(g(x)) = \sqrt{x - 3} + 1
Domain: x3\displaystyle x \geq 3

gf=g(f(x))=x+13=x2\displaystyle g \circ f = g(f(x)) = \sqrt{x + 1 - 3} = \sqrt{x - 2}
Domain: x2\displaystyle x \geq 2

is my analize correct?😣
Yes.

-Dan
 
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