Complex Transformation: sketch locus of W = Z*, | Z-3i | = 2

Tico

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Feb 26, 2008
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Hi, I did this question today. I did it two ways and then found that I got different answers. I asked my teacher and he couldn't really come up with a reason why.

W=Z* and | Z -3i | = 2 (modulus of (z-3i) =2)

Sketch the locus of W.

My first method was,

Z = U +iV
| U + (V-3)i | = 2
U^2 + (V-3)^2 = 4

and then W is the complex conjigate, giving a circle of

U^2 + (V+3)^2 = 4

My other method was to find the conjigate straight away.

Z = U +iV

| Z + 3i | = | Z* - 3i | (That's easily enough proved given a sheet of papers)
Z* = U -iV
| U + (3-V)i | = 2

U^2 + (3-V)^2 = 4

But surely I've already substituted in for Z* and shouldn't have to reflect it using this method?

If anyone could explain I'd be very grateful. Thank you in advance.
 
Re: Complex Transformation

The conjugate operation is simply a reflection in the real axis.
The set of points |z-3i|=2 is a circle centered at 3i with radius 2.
If you graph this, you will see.
 
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