Complex Numbers, Complex Plane, and Finding a Slope

skyd92

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Jun 29, 2009
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I have had soooo much trouble with this problem it is not even funny. I have tried working with a tutor, but they couldn't figure it out either, nor does the book explain how to even get started. I don't even know where to begin. HELP!

Problem: Find the slope of the line joining the points representing 2-3i and -(square root of 2)+i on the complex plane.

I can't put in the actual radical sign so I just typed "square root of" instead.
 
Find the slope of the two points (2-3i,-?2+i) in the Argand plane.

From the given complex numbers, we can derive the points in the plane as (2,-3) and (-?2,1).

Hence, m = -2(2-?2) = -1.17157287525....
 
skyd92 said:
Problem: Find the slope of the line joining the points representing 2-3i and -(square root of 2)+i on the complex plane.
Can you find the slope given two points in a plane?
\(\displaystyle (2,-3)~\&~(\sqrt{2},1)\text{ then the slope is }m=\frac{1-(-3)}{\sqrt{2}-2}\).
 
Thanks for all of the help! It really cleared all of my questions up! :mrgreen:
 
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