complex fraction

[kappri]

Having trouble with this one Can you solve for me please

1 4
___ + ___
a 3b
___________________
1 3
____ - ___
2a b




Just checking on the answer for this one. Could you solve for me please

3 = 5
_____ ____
x-3 x+4


Thanks for your help

 

[kappri]

Re: complex fractions

Need help with the following 2 problems. Thanks

 

[Aladdin]

Having trouble with this one Can you solve for me please

1 4
___ + ___
a 3b
___________________
1 3
____ - ___
2a b




Just checking on the answer for this one. Could you solve for me please

3 = 5
_____ ____
x-3 x+4


Thanks for your help

We wont guess here, please write the problem in a suitable correct way.

 

[Aladdin]

Having trouble with this one Can you solve for me please

1 4
___ + ___
a 3b
___________________
1 3
____ - ___2a b




Just checking on the answer for this one. Could you solve for me please

3 = 5
_____ ____---> (3)/(x-3)=(5)(x+4) : (3)(x+4)=(5)/(x-3) : 3x+12= 5x-15 : 3x-5x=-15-12 : -2x=-27 : x=27/2
x-3 x+4

Ok Denis :wink:

Thanks for your help

 

[Loren]

Having trouble with this one Can you solve for me please

1 4
___ + ___
a 3b
___________________
1 3
____ - ___
2a b
Determine the lcd of all the simple fractions. In this case it is 6ab. Multiply numerator and denominator of the complex fraction by this lcd.

$\displaystyle \frac{\frac{6ab}{1}\cdot (\frac{1}{a}+\frac{4}{3b})}{\frac{6ab}{1}\cdot(\frac{1}{2a}-\frac{3}{b})}=\frac{6b+2a}{3b-18a}=$

and you can take it from there???
Was there a typo in the original problem?




Just checking on the answer for this one. Could you solve for me please

3 = 5
_____ ____
x-3 x+4

I get x=27/2


Thanks for your help