greatwhiteshark
Full Member
- Joined
- May 8, 2005
- Messages
- 279
I have two questions below. I will show partial work for each question.
I will NOT type the complex root formula (too BIG). I will display my answers per question. Can someone please check to see if I found the right complex roots for each question?
1) Find the complex fourth root of -2 + 3i.
n = 4
k = 0, 1, 2, and 3 = four roots
radius = sqrt{13}
I am in quadrant 2 where my reference angle = 3/-2, right?
Theta = 180 degrees - my reference angle, right?
Thus, theta = 179.974 degrees. Is this correct so far?
My Answers: d = degrees
First root = 13^1/4 (cos44.994d + i sin 44.994d)
Second root: 13^1/4 (cos134.994d + i sin 134.994d)
Third root: 13^1/4 (cos 224.994d + i sin224.994d)
Fourth root: 13^1/4 (cos314.994d + i sin314.994d)
Is this correct? If not where did I get lost?
Here's my second question:
2) Find the complex cube root of -1 +sqrt{3}i
n = 3
k = 0, 1 and 2
radius = 2
I am in the second quadrant, right? So, my reference angle = -60 degrees. Here theta = 120 degrees = the initial angle, right?
MY ANSWERS: d = degrees
First root: 2^1/3 (cos40d + i sin40d)
Second root: 2^1/3 (cos160d + i sin160d)
Third root: 2^1/3 (cos 280d + i sin280d)
Is this correct? If not, where did I go wrong?
I will NOT type the complex root formula (too BIG). I will display my answers per question. Can someone please check to see if I found the right complex roots for each question?
1) Find the complex fourth root of -2 + 3i.
n = 4
k = 0, 1, 2, and 3 = four roots
radius = sqrt{13}
I am in quadrant 2 where my reference angle = 3/-2, right?
Theta = 180 degrees - my reference angle, right?
Thus, theta = 179.974 degrees. Is this correct so far?
My Answers: d = degrees
First root = 13^1/4 (cos44.994d + i sin 44.994d)
Second root: 13^1/4 (cos134.994d + i sin 134.994d)
Third root: 13^1/4 (cos 224.994d + i sin224.994d)
Fourth root: 13^1/4 (cos314.994d + i sin314.994d)
Is this correct? If not where did I get lost?
Here's my second question:
2) Find the complex cube root of -1 +sqrt{3}i
n = 3
k = 0, 1 and 2
radius = 2
I am in the second quadrant, right? So, my reference angle = -60 degrees. Here theta = 120 degrees = the initial angle, right?
MY ANSWERS: d = degrees
First root: 2^1/3 (cos40d + i sin40d)
Second root: 2^1/3 (cos160d + i sin160d)
Third root: 2^1/3 (cos 280d + i sin280d)
Is this correct? If not, where did I go wrong?